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个人简介
if(ij){ dp[i][j]=1; } if(j0||j==1){ dp[i][j]=1; } else if(i<j){ dp[i][j]=0; }
dp[i][j]=(dp[i-j][j]%mod+dp[i-1][j-1]%mod)%mod;
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通过的题目
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最近活动
This person is lazy and didn't join any contests or homework. -
最近编写的题解
This person is lazy and didn't write any solutions.
题目标签
- 系统测试
- 1